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Henry Nebrensky

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Message 49898 - Posted: 6 Apr 2024, 10:25:16 UTC

Hi all,

Does anybody here know roughly what the maximum "physics energy" is for an LHC proton-proton collision?

Since protons are composite particles the collisions are actually between individual quarks/gluons/whatever, and I'd like to get an idea of the "inefficiency" compared to the beam proton energy.

I couldn't see this in a quick look at Wikipedia, probably because I'm not sure what the technical terms would be!

Thanks
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computezrmle
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Message 49899 - Posted: 6 Apr 2024, 11:09:04 UTC - in response to Message 49898.  

Take a look at this dokument:
https://cds.cern.ch/record/2809109/files/CERN-Brochure-2021-004-Eng.pdf
Especially pages 12 and 21.
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Henry Nebrensky

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Message 49951 - Posted: 16 Apr 2024, 10:48:11 UTC - in response to Message 49899.  

Thanks for that - I'll have to read it through properly.
It's nice to see LHC experiments other than the big four get a mention.

For reference., p21 answers a similar question I think: Lead-Lead has a total of 1150 TeV available but there is actually only 5.02 TeV available to the colliding pair of nucleons within; possibly I'm misunderstanding the physics but shouldn't there be a similar downshift between the overall proton(nucleon) energy and that of the actual colliding constituents?
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Message boards : LHC@home Science : Collision energies


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