LHC@home

My Theory is devoloped from special relativity equation
{p^2-e^2/c^2 }lhc= {p^2-e^2/c^2 }cosmic ray
Hire energy of hadron that is proton is 14TeV
Net Momentum of hadron is zero. That of
Momentum conservation
Therefore {-〖14〗^2/c^2 }proton={p^2-e^2/c^2 }cosmic ray
In the case of cosmic ray
Net momentum, P = P ray + Pproton
That is P = P ray + 0
Net energy, E=E ray+M proton C^2
-〖14〗^2/c^2 ={P^2 ray-(Eray+MpC^2 )^2/c^2 }
-〖14〗^2=p^2 ray C^2- (Eray+Mp C^2 )^2
-196=P^2 ray C^2- (E^2+M^2 p C^4+2Mp C^2 E) ---(2)
But E^2 ray≫Mp^2 C^4 (P^2 ray≅E^2 ray)
(2)=> 196 = 2Mp C^2 Eray -------(3)
For protons, E = 〖10〗^(-3) TeV
From (3) Energy ≅〖10〗^17 eV
From differential energy spectrum of cosmic rays, (Conceder the energy of cosmic rays ≫〖10〗^17 eV


From the graph ,
Flux of cosmic ray is the area of the triangle is the flux.
Flux = 1/2*( 〖10〗^(-20)*〖10〗^10 )
Flux ≅〖10〗^(-10)
Conceder sun is a gind magnet and it absorbs cosmic rays
Radios of sun = 7*〖10〗^8 M
Surface area of sun = 4π * 〖(10〗^(8)2)
≅6 *〖10〗^18
No of collisions = flux*surface area
= 〖10〗^(-10)*6*〖10〗^18
≅〖10〗^9 collisions
〖10〗^9 collisions occers in sun. That means the same risk is in Sun. we don’t detected any black holes in sun. and sun is safe too. Then how the LHC is riskyer because of BLACK HOLES

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A graviton should have zero mass and spin 2. A Higgs boson nonzero mass and spin 1, AFAIK.
Tullio

A Higgs boson nonzero mass and spin 1, AFAIK.
Tullio

No. A Higgs Boson will have spin 0.
See here:
http://arxiv.org/abs/1003.0904
hope this helps
dr.mabuse

A Higgs boson nonzero mass and spin 1, AFAIK.
Tullio

No. A Higgs Boson will have spin 0.
See here:
http://arxiv.org/abs/1003.0904
hope this helps
dr.mabuse

Your are right, if it exists, of course.
Tullio